A+(2X^2-Y^5)=5X^2-3X^2+2XY
7) tính a)(2xy+5)(4x^2+5) b)(6xy+4)(2x^2+1) c)(9x^2+4)(3x+5) d)(-2xy+6)(1/2xy+7) e)(4x+1)(2x^2+5x+2) f)(2x^2y+3x)(2x+1) g)(4xy+5x^2y)(2xy+6) h)(-1/2x^2+6)(4xy+5)
a) (2xy+5)(4x^2+5): = 2xy * 4x^2 + 2xy * 5 + 5 * 4x^2 + 5 * 5 = 8x^3y + 10xy + 20x^2 + 25 b) (6xy+4)(2x^2+1): = 6xy * 2x^2 + 6xy * 1 + 4 * 2x^2 + 4 * 1 = 12x^3y + 6xy + 8x^2 + 4 c) (9x^2+4)(3x+5): = 9x^2 * 3x + 9x^2 * 5 + 4 * 3x + 4 * 5 = 27x^3 + 45x^2 + 12x + 20 d) (-2xy+6)(1/2xy+7): = -2xy * 1/2xy + (-2xy) * 7 + 6 * 1/2xy + 6 * 7 = -xy + (-14xy) + 3 + 42 = -15xy + 45 e) (4x+1)(2x^2+5x+2): = 4x * 2x^2 + 4x * 5x + 4x * 2 + 1 * 2x^2 + 1 * 5x + 1 * 2 = 8x^3 + 20x^2 + 8x + 2x^2 + 5x + 2 = 8x^3 + 22x^2 + 13x + 2 f) (2x^2y+3x)(2x+1): = 2x^2y * 2x + 2x^2y * 1 + 3x * 2x + 3x * 1 = 4x^3y + 2x^2y + 6x^2 + 3x g) (4xy+5x^2y)(2xy+6): = 4xy * 2xy + 4xy * 6 + 5x^2y * 2xy + 5x^2y * 6 = 8x^2y^2 + 24xy + 10x^3y + 30x^2y = 8x^2y^2 + 30x^2y + 24xy h) (-1/2x^2+6)(4xy+5): = -1/2x^2 * 4xy + (-1/2x^2) * 5 + 6 * 4xy + 6 * 5 = -2xy + (-5/2x^2) + 24xy + 30 = 22xy + (-5/2x^2) + 30
a) 3x(x+1)-x(3x+2)
b) 2x(x2-5x+6)+(x-1)(x+3)
c) (x2-xy+y2)-(x2+2xy+y2)
d) (2/5xy+x-y)-(3x+4y)-2/5xy
e) 2xy(x2-4xy+4y2)
f) (x+y)(xy+5)
g) (x3-2x2-x+2):(x-1)
h) (2x2+3x-2):(2x-1)
a) 3x 2 (2x 3 – x + 5)
b) (4xy + 3y – 5x)x 2 y
c) (3x 2 y – 6xy + 9x)(- 3
4
xy)
d) - 3
1
xz(- 9xy + 15yz) + 3x 2 (2yz 2 – yz)
e) (x 3 + 5x 2 – 2x + 1)(x – 7)
f) (2x 2 – 3xy + y 2 )(x + y)
g) (x – 2)(x 2 – 5x + 1) – x(x 2 + 11)
h) [(x 2 – 2xy + 2y 2 )(x + 2y) - (x 2 + 4y 2 )(x – y)] 2xy
Mọi người giúp em với ạ
Đề bài là gì sao không ghi rõ??
Thu gọn các biểu thức : a) 6x^2y(3xy-2xy^2+y) b) (-3x+2)(5x^2-1/3x+4) c) (x+1)(x-2)+x(3-x) d) (2x+3)^2-(2x-5)(2x+5)-(x-1)(x^12+12)
a: =18x^3y^2-12x^3y^3+6x^2y^2
b: (-3x+2)(5x^2-1/3x+4)
=-12x^3+x^2-12x+10x^2-2/3x+8
=-12x^3+11x^2-38/3x+8
c: =x^2-x-2+3x-x^2
=2x-2
d: =4x^2+12x+9-4x^2+25-(x-1)(x^2+12)
=12x+34-x^3-12x+x^2+12
=-x^3+x^2+46
6) Tính a)2xy(3x+1) b)-6x^2y(4x-5) c)-3x^2(4x^2y-6xy) d1/2xy^2(2x+3) e)8x^2y^2(1/4xy-1/2x^2) f)5x(x^2+3x+1) g)-1/2x^2y(2xy+6)
Để tính các biểu thức trên, ta sẽ áp dụng quy tắc nhân đa thức.
a) 2xy(3x+1) = 6x^2y + 2xy
b) -6x^2y(4x-5) = -24x^3y + 30x^2y
c) -3x^2(4x^2y-6xy) = -12x^4y + 18x^3y
d) 1/2xy^2(2x+3) = xy^2 + 3/2xy^2
e) 8x^2y^2(1/4xy-1/2x^2) = 2xy - 4x^2y^2
f) 5x(x^2+3x+1) = 5x^3 + 15x^2 + 5x
g) -1/2x^2y(2xy+6) = -x^3y - 3x^2y
Tìm x,y,z biết: a) x^2+y^2-4x+4y+8=0 b) 5x^2-4xy+y^2=0 c) x^2+2y^2+z^2-2xy-2y-4z+5=0 d) 3x^2+3y^2+3xy-3x+3y+3=0 e) 2x^2+y^2+2z^2-2xy-2xz+2yz-2z-2z-2x+2=0
a) x2+y2-4x+4y+8=0
⇔ (x-2)2+(y+2)2=0
\(\Leftrightarrow\left\{{}\begin{matrix}x-2=0\\y+2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=-2\end{matrix}\right.\)
b)5x2-4xy+y2=0
⇔ x2+(2x-y)2=0
\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\2x-y=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\y=0\end{matrix}\right.\)
c)x2+2y2+z2-2xy-2y-4z+5=0
⇔ (x-y)2+(y-1)2+(z-2)2=0
\(\Leftrightarrow\left\{{}\begin{matrix}x-y=0\\y-1=0\\z-2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=y=1\\z=2\end{matrix}\right.\)
b: Ta có: \(5x^2-4xy+y^2=0\)
\(\Leftrightarrow x^2-\dfrac{4}{5}xy+y^2=0\)
\(\Leftrightarrow x^2-2\cdot x\cdot\dfrac{2}{5}y+\dfrac{4}{25}y^2+\dfrac{21}{25}y^2=0\)
\(\Leftrightarrow\left(x-\dfrac{2}{5}y\right)^2+\dfrac{21}{25}y^2=0\)
Dấu '=' xảy ra khi \(\left\{{}\begin{matrix}x=0\\y=0\end{matrix}\right.\)
d)3x2+3y2+3xy-3x+3y+3=0
⇔ 6x2+6y2+6xy-6x+6y+6=0
⇔ 3(x+y)2+3(x-1)2+3(y+1)2=0
\(\Leftrightarrow\left\{{}\begin{matrix}x+y=0\\x-1=0\\y+1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=-1\end{matrix}\right.\)
Bài 3: Tìm bậc của các đa thức sau:
a) 2x – 5xy + 3x 2
b) ax 3 + 2xy – 5 ( a là hằng số)
c) 5x 3 – 4x + 7x 2 – 8x 3 + 4x + 1 – 5x 2
d) -3x 5 - x 3 y - xy 2 + 3x 5 + 2
a)bậc 2
b) bậc 2
c)bậc 3
d) bậc 2
a, \(2x-5xy+3x^2\)Bậc : 2
b, \(ax^3+2xy-5\)Bậc : 3
c, \(5x^3-4x+7x^2-8x^3+4x+1-5x^2=-3x^3+2x^2+1\)Bậc : 3
d, \(-3x^5-x^3y-xy^2+3x^5+2=-x^3y-xy^2+2\)Bậc : 4
Giúp mình nhé
Thực hiên phép tính
a/ 2x(3x^2-5x+3)
b/ -2x(x^2+5x-3)
c/ -1/2x^2(2x^3-4x+3)
d/ (2x-1)(x^2+5-4)
e/ -(5x-4)(2x+3)
f/ (2x-y)(4x^2-2xy+y^2)
g/(3x-4)(x+4)+(5-x)(2x^2+3x-1)
e/7x(x-4)-(7x+3)(2x^2-x+4)
\(a. 2x(3x^2-5x+3) = 6x^3-10x^2+6x \)
\(b. -2x(x^2+5x-3) = -2x^3-10x^2+6x\)
c. \(-\dfrac{1}{2}x^2\left(2x^3-4x+3\right)
=-x^5+2x^3-\dfrac{3}{2}x^2\)
\(d.\left(2x-1\right)\left(x^2+5-4\right)=\left(2x-1\right)\left(x^2+1\right)=2x^3+2x-x^2-1\)
e. \(-\left(5x-4\right)\left(2x+3\right)=10x^2+15x-8x-12=-10x^2+7x-12\)
f.\(\left(2x-y\right)\left(4x^2-2xy+y^2\right)=\left(2x-y\right)\left(2x-y\right)^2=\left(2x-y\right)^3\)
g.\(\left(3x-4\right)\left(x+4\right)+\left(5-x\right)\left(2x^2+3x-1\right)=3x^2+12x-4x-16+10x^2+15x-5-2x^3-3x^2+x=-2x^3+10x^2+24x-21\)
e. \(7x\left(x-4\right)-\left(7x+3\right)\left(2x^2-x+4\right)=7x^2-28x-14x^3+7x^2-28x-6x^2+3x+-12=-14x^3+8x^2-53x-12\)
a)x^2yz-x^3y^3z+xyz^2
b)3x^2-6xy+15xy^2z
c)2x(x-4)-5(4-x)-(2x+5)(7-5x)
d)16x^2-24xy+9x^2
e)49-x^2-2xy-y^2
e: \(49-x^2-2xy-y^2\)
\(=49-\left(x+y\right)^2\)
\(=\left(7-x-y\right)\left(7+x+y\right)\)
d: \(16x^2-24xy+9y^2=\left(4x-3y\right)^2\)
a)=xyz(x-x^2y^2+z)
e)=72+(x-y)2
[7+(y-x)].[(7-(y-x)] còn lại tự làm ;)